Multiple choice

Ritu is $5$ years younger than her brother Rohit. Their father is $25$ years older than Ritu. Four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu then, Find present age of each.

  1. Ritu $=12$ year , Rohit $=18$ years and father $=40$ years
  2. Ritu $=9$ year , Rohit $=14$ years and father $=34$ years
  3. Ritu $=10$ year , Rohit $=19$ years and father $=44$ years
  4. Ritu $=11$ year , Rohit $=16$ years and father $=37$ years
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B Correct answer
Explanation

Let Ritu = x, Rohit = x + 5, Father = x + 25. Four years ago: Ritu = x - 4, Rohit = x + 1, Father = x + 21. Equation: x + 21 = 2 * (x - 4 + x + 1) = 2 * (2x - 3) = 4x - 6. 3x = 27, x = 9. Ritu = 9, Rohit = 14, Father = 34.

AI explanation

Let Ritu's present age be R, Rohit's be R + 5, and their father's be R + 25. Four years ago, the father's age was R + 21, and the sum of Ritu's and Rohit's ages was (R - 4) + (R + 1) = 2R - 3. The equation is R + 21 = 2 * (2R - 3), which simplifies to R + 21 = 4R - 6. Solving for R gives 3R = 27, so R = 9. The present ages are Ritu = 9 years, Rohit = 9 + 5 = 14 years, and father = 9 + 25 = 34 years.

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