A mans age is now four times that of his son and it is also three times that of his daughter In six years time it will be three times that of his son How old was he when his daughter was born?

Let the son's current age be s and the daughter's be d, making the man's current age 4s and also 3d, so 4s equals 3d. In six years, his age will be 4s + 6, which equals three times his son's age in six years, giving the equation 4s + 6 = 3(s + 6). Solving this equation yields 4s + 6 = 3s + 18, so s = 12; this means the man's current age is 4 times 12, or 48 years. Since 3d equals 48, the daughter is currently 16 years old. When she was born 16 years ago, the father was 48 minus 16 years old, making him 32 years old.

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