$A$ is $25$ years older than $B$. In $15$ years, $A$ will be twice of $B$. Find the present ages of $A$ and $B$.
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$A$ is $25$ years older than $B$. In $15$ years, $A$ will be twice of $B$. Find the present ages of $A$ and $B$.
A = B + 25. (A + 15) = 2(B + 15). Substitute: B + 25 + 15 = 2B + 30. B + 40 = 2B + 30. B = 10. A = 35.
Let the present age of B be x years, making the age of A equal to x plus 25. In 15 years, the equation is x plus 25 plus 15 equals 2 times x plus 15. Simplifying gives x plus 40 equals 2x plus 30, so x equals 10. The present age of A is 10 plus 25, which is 35 years, and the present age of B is 10 years.