Multiple choice

A man is $24$ years older than his son. $12$ years ago, he was five times as old as his son. Find the present ages of both.

  1. Present age of father is $44$ years and Present age of son is $20$ years
  2. Present age of father is $42$ years and Present age of son is $18$ years
  3. Present age of father is $60$ years and Present age of son is $36$ years
  4. Present age of father is $48$ years and Present age of son is $24$ years
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B Correct answer
Explanation

Let son's age be x, father's be x + 24. 12 years ago: (x + 24 - 12) = 5(x - 12). x + 12 = 5x - 60. 4x = 72, so x = 18. Father = 18 + 24 = 42.

AI explanation

Let the present age of the son be x years, making the father's age x plus 24. Twelve years ago, the equation is x plus 12 equals 5 times x minus 12. Expanding gives x plus 12 equals 5x minus 60, so 4x equals 72 and x equals 18. The present age of the father is 18 plus 24, which is 42 years, and the present age of the son is 18 years.

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