Multiple choice

In a bag there are $6$ white and $4$ black balls. Two balls are drawn one after another without replacement.If the 1st ball is known to be white, the probability that the 2nd ball drawn is also white is

  1. $\displaystyle \frac{2}{9}$
  2. $\displaystyle \frac{5}{9}$
  3. $\displaystyle \frac{8}{9}$
  4. $\displaystyle \frac{8}{13}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initially there are 10 balls (6 white, 4 black). If one white ball is removed, 9 balls remain, 5 of which are white. The probability of drawing a white ball next is 5/9.

AI explanation

Using the conditional probability method, if the first ball drawn is white, there are 5 white balls left from a new total of 9 balls. The probability of drawing a second white ball is simply the number of remaining white balls divided by the new total. Therefore, the required probability is 5/9.

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