Multiple choice

The chance of throwing an ace is the first only of two successive throws with an ordinary die is

  1. $\displaystyle \frac{1}{36}$
  2. $\displaystyle \frac{5}{36}$
  3. $\displaystyle \frac{25}{36}$
  4. $\displaystyle \frac{1}{6}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The required event is an ace on the first throw and not an ace on the second throw. Its probability is 1/6 × 5/6 = 5/36, so option B is correct.

AI explanation

The probability of getting an ace on the first throw and a non-ace on the second throw is found by multiplying the probabilities of these two independent events. The probability of an ace on the first throw is 1/6. The probability of a non-ace on the second throw is 5/6. Multiplying 1/6 by 5/6 gives 5/36. The probability of throwing an ace in the first only of two successive throws is 5/36.

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