The probability of getting at least one head when we toss $5$ unbiased coin is
- $\dfrac{5}{32}$
- $\dfrac{1}{32}$
- $\dfrac{31}{32}$
- $\dfrac{4}{32}$
Reveal answer
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C
Correct answer
Explanation
The probability of getting at least one head is 1 minus the probability of getting no heads. For 5 coins, the probability of no heads (all tails) is (1/2)^5 = 1/32. Thus, the probability of at least one head is 1 - 1/32 = 31/32.
AI explanation
The total number of possible outcomes when tossing 5 unbiased coins is 2 to the power of 5, which equals 32. Using the complementary event method, it is easier to calculate the probability of getting zero heads (all tails) and subtract it from 1. The probability of getting all tails is 1 out of 32, so the probability of getting at least one head is 1 minus 1/32, which equals 31/32. The probability is 31/32.