If the points (1,1) (2,3) and (5,-1) form a right triangle, then the hypotenuse is of length
Reveal answer
Fill a bubble to check yourself
If the points (1,1) (2,3) and (5,-1) form a right triangle, then the hypotenuse is of length
3
4
6
5
Calculate squared distances between points: A(1,1), B(2,3), C(5,-1). AB^2 = (2-1)^2 + (3-1)^2 = 1+4=5. BC^2 = (5-2)^2 + (-1-3)^2 = 9+16=25. AC^2 = (5-1)^2 + (-1-1)^2 = 16+4=20. Since AB^2 + AC^2 = 5 + 20 = 25 = BC^2, BC is the hypotenuse. Length = sqrt(25) = 5.
Find the lengths of the sides of the triangle using the distance formula. The distance between (1, 1) and (2, 3) is the square root of 5, between (2, 3) and (5, -1) is 5, and between (1, 1) and (5, -1) is the square root of 20. Since (5 squared) plus ((square root of 5) squared) equals (square root of 20 squared), the triangle is right-angled with the side connecting (2, 3) and (5, -1) as the hypotenuse. Therefore, the hypotenuse is 5.