Multiple choice

Two trains travel in the same direction at $56\ km$ and $29\ km$ an hour and the faster train passes a man in the slower train in $16 seconds$. Find the length of the faster train

  1. $200\ m$
  2. $240\ m$
  3. $120\ m$
  4. $112\ m$
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C Correct answer
Explanation

The relative speed of the faster train with respect to the man in the slower train is 56 - 29 = 27 km/hr. Converting to m/s: 27 * (5/18) = 7.5 m/s. Length = speed * time = 7.5 * 16 = 120 m.

AI explanation

The relative speed of the trains moving in the same direction is the difference in their speeds, which is 56 km/hr minus 29 km/hr, equaling 27 km/hr. Converting 27 km/hr to m/s gives 27 multiplied by 5/18, which results in 7.5 m/s. Since the faster train takes 16 seconds to pass the man, its length equals relative speed multiplied by time, calculating as 7.5 m/s multiplied by 16 s, giving a length of 120 m.

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