The median of the observations $30, 91, 0, 64, 42, 80, 30, 5, 117, 71$ is __________.
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The median of the observations $30, 91, 0, 64, 42, 80, 30, 5, 117, 71$ is __________.
First, arrange the 10 observations in ascending order: 0, 5, 30, 30, 42, 64, 71, 80, 91, 117. Since there is an even number of observations, the median is the average of the 5th and 6th terms: (42 + 64) / 2 = 106 / 2 = 53.
Arrange the observations in ascending order to get 0, 5, 30, 30, 42, 64, 71, 80, 91, 117. With 10 observations, the median is the average of the 5th and 6th terms. The 5th term is 42 and the 6th term is 64, so the median is (42 + 64) / 2 = 106 / 2 = 53.