Multiple choice

A train $'X'$ leaves station $'A'$ at $3$ p.m and reaches station $'B'$ at $4.30$ p.m., while another train $'Y'$ leaves station $'B'$ at $3.00 p.m$ and reaches station $'A'$ at $4.00 p.m.$These two trains cross each other at :

  1. $3.36 p.m$
  2. $3.30 p.m$
  3. $3.20 pm$
  4. $3.40 pm$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Train X speed = D/1.5. Train Y speed = D/1. Relative speed = D(1/1.5 + 1) = D(5/3). Distance = D. Time = D / (5D/3) = 3/5 hours = 36 minutes. 3:00 PM + 36 min = 3:36 PM.

AI explanation

Using the formula distance equals speed multiplied by time, we let the total distance be D and find the speed of train X is D over 90 while the speed of train Y is D over 60. When they travel towards each other, their relative speed is D over 90 plus D over 60, which equals D over 36 per hour. By the formula time equals distance divided by relative speed, the time taken to meet is D divided by (D over 36), which equals 36 minutes. Adding 36 minutes to the departure time of 3 p.m. results in a crossing time of 3.36 p.m.

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