Multiple choice

The population of a place increased to 54000 in 2003 at a rate of 5% per annum. Find the population in 2001.

  1. 48980 (approx)

  2. 46480 (approx)

  3. 49910 (approx)

  4. 47970 (approx)
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A Correct answer
Explanation

54000 = P * (1 + 5/100)^2. 54000 = P * (1.05)^2 = P * 1.1025. P = 54000 / 1.1025 = 48979.59.

AI explanation

This problem requires working backward two years at a 5% growth rate, meaning the 2001 population equals 54,000 divided by 1.05, and then divided by 1.05 again. This evaluates to 54,000 divided by 1.1025, which equals approximately 48,979.59. The result is 48980 (approx).

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