Calculate the mean deviation about mean for the data given here: Class interval $5$ $15$ $25$ $35$ $45$ Frequency $5$ $3$ $9$ $12$ $6$

The mean is calculated as (5*5 + 15*3 + 25*9 + 35*12 + 45*6) / (5 + 3 + 9 + 12 + 6), which gives 960 / 35 = 27.43. The mean deviation about the mean requires finding the sum of the absolute differences between each value and 27.43, which is |5 - 27.43|*5 + |15 - 27.43|*3 + |25 - 27.43|*9 + |35 - 27.43|*12 + |45 - 27.43|*6, equaling 364.28. Dividing this by the total frequency of 35 results in a mean deviation of 10.4.

• Thanks
• Wrong explanation