Multiple choice

$\dfrac{5}{9}$ part of the population in a village are males. If $30\%$ of the males are married, the percentage of unmarried females in the total population is?

  1. $20\%$
  2. $27\dfrac{7}{9}\%$
  3. $40\%$
  4. $70\%$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let total population be 9. Males = 5, Females = 4. Married males = 30% of 5 = 1.5. Since each married male has one wife, married females = 1.5. Unmarried females = Total females - Married females = 4 - 1.5 = 2.5. Percentage of unmarried females = (2.5 / 9) * 100 = 250/9 = 27 7/9%.

AI explanation

Assume the total population of the village is 900, meaning the number of males is (5 divided by 9) multiplied by 900, which is 500, and the number of females is 400. Assuming monogamy, since 30 percent of the 500 males are married, there are 150 married males and thus 150 married females; this leaves 250 unmarried females. The required percentage is (250 divided by 900) multiplied by 100, which equals 27 and 7/9 percent.

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