Multiple choice

The present population of a village is 60,500 and it increases at the rate 10% per annum. What was the population 2 years ago?

  1. 55,000

  2. 60,000

  3. 50,000

  4. 52,000
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let P be the population 2 years ago. P * (1 + 10/100)^2 = 60500. P * (1.1)^2 = 60500. P * 1.21 = 60500. P = 60500 / 1.21 = 50000.

AI explanation

Using the population growth formula in reverse, if the population grows at 10% per annum, the population 2 years ago multiplied by (1 + 10/100)^2 equals the present population. This gives the equation P * 1.1^2 = 60500, which simplifies to P * 1.21 = 60500. Solving for P, we get P = 60500 / 1.21 = 50000. The population 2 years ago was 50,000.

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