Determine the frequency $k$ lies,if mean deviation about median is 10. $x$ $7.5-12.5$ $12.5-17.5$ $17.5-22.5$ $22.5-27.5$ $27.5-32.5$ $32.5-37.5$ $37.5-42.5$ $42.5-47.5$ $f$ $7$ $k$ $8$ $5$ $6$ $8$ $4$ $9$

Testing k equals 3 gives a total frequency of 50, so the median is the 25th value, falling in the 17.5 to 22.5 class with a median value of 20. The sum of frequency times absolute deviation from 20 is 500, and dividing by the total frequency 50 gives 10, proving k is 3.

• Thanks
• Wrong explanation