This is an arithmetic progression with first term a = 425, last term l = 495, and common difference d = 5. The number of terms n = ((495 - 425) / 5) + 1 = 14 + 1 = 15. The mean of an AP is (a + l) / 2 = (425 + 495) / 2 = 920 / 2 = 460.
The given sequence 425, 430, 435, up to 495 is an arithmetic progression. The mean of an arithmetic progression is the average of its first and last terms. Applying this property, we calculate the mean as 425 plus 495 divided by 2, which equals 920 divided by 2, resulting in a mean of 460.