Mean of 'n' items is $\bar{x}$. If these n items are successively increased by $2, 2^2, 2^3$,.... $2^n$, then the new mean is?
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Mean of 'n' items is $\bar{x}$. If these n items are successively increased by $2, 2^2, 2^3$,.... $2^n$, then the new mean is?
The original sum of n items is n * x_bar. The new sum is (n * x_bar) + (2 + 2^2 + ... + 2^n). The sum of the geometric series 2 + 2^2 + ... + 2^n is 2 * (2^n - 1) / (2 - 1) = 2^(n+1) - 2. The new mean is (n * x_bar + 2^(n+1) - 2) / n = x_bar + (2^(n+1) - 2) / n, which simplifies to x_bar + 2^(n+1)/n - 2/n.
The new mean is calculated as the sum of the original items plus the sum of the added geometric progression, all divided by n. The sum of the original n items is n times x-bar, and the sum of the geometric series 2, 2^2, ..., 2^n is 2^(n+1) - 2. Combining these, the new sum is n*x-bar + 2^(n+1) - 2, so dividing by n gives the new mean as x-bar + 2^(n+1)/n - 2/n.