Multiple choice

Class Interval Frequency 100-12 12 120-140 14 140-160 8 160-180 6 180-200 10 mean is 145.20 If true then enter $1$ and if false then enter $0$

  1. non of thease

  2. 0

  3. 1

  4. can not det
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using class midpoints 110, 130, 150, 170, and 190, the weighted total is 7260 and the total frequency is 50. The mean is 7260/50 = 145.2, so the statement is true and the required entry is 1.

AI explanation

To find the mean of the grouped frequency distribution, use the assumed mean method or direct method with class marks (110, 130, 150, 170, 190). The sum of the products of class marks and their corresponding frequencies (12, 14, 8, 6, 10) is (110*12) + (130*14) + (150*8) + (170*6) + (190*10) = 1320 + 1820 + 1200 + 1020 + 1900 = 7260. The total frequency is 12 + 14 + 8 + 6 + 10 = 50. Dividing the total sum by the total frequency gives 7260 / 50 = 145.20, so the statement is true.

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