Multiple choice Between 4 and 5 o'clock, when the hands will be inclined at $60^o$ for the first time? $10 \cfrac{10}{11}$ min. past 4 $11 \cfrac{10}{11}$ min. past 4 $12$ min. past 4 $9 \cfrac{10}{11}$ min. past 4 Reveal answer Fill a bubble to check yourself A Correct answer Explanation At 4 o'clock, the hands are 20 minute spaces apart. For a 60 degree angle, they must be 10 minute spaces apart. The minute hand must gain 10 minute spaces. Time = 10 * (60/55) = 120/11 = 10 and 10/11 minutes past 4.