Multiple choice

$AB$ and $CD$ are two vertical poles of height $6m$ and $11m$ respectively. If the distance between their feet is $12m$, find the distance between their tops.

  1. $13m$
  2. $5m$
  3. $11m$
  4. $12m$
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A Correct answer
Explanation

The horizontal distance between the poles is 12m. The vertical difference in height is 11-6 = 5m. The distance between the tops is the hypotenuse of a right triangle with legs 12m and 5m. sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13m.

AI explanation

The horizontal distance between the two vertical poles AB and CD is 12 m, and the difference in their heights is 11 m minus 6 m, which equals 5 m. The segment connecting their tops forms the hypotenuse of a right triangle with a base of 12 m and a height of 5 m. Using the Pythagorean theorem, the distance between the tops is the square root of (12 squared + 5 squared), which equals the square root of 169. Therefore, the distance between their tops is 13 m.

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