Multiple choice

The height of a tower is $50\sqrt {3}\ m$. The angle of elevation of a tower from a distance $50\ m$ from its feet is

  1. $30^{\circ}$
  2. $45^{\circ}$
  3. $60^{\circ}$
  4. $90^{\circ}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

tan(theta) = height / distance = 50*sqrt(3) / 50 = sqrt(3). theta = 60 degrees.

AI explanation

The angle of elevation is found by applying the tangent ratio to the right triangle formed by the height of the tower and the horizontal distance. The tangent of the angle equals the height divided by the base, which is 50 times the square root of 3 divided by 50. This simplifies to the square root of 3, meaning the angle is 60 degrees.

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