Multiple choice

A pendulum clock loses 12 s a day if the temperature is ${40^ \circ }C$ and gains 4 s a day if the temperature is ${20^ \circ }C$. The temperature at which the clock will show correct time, and the co-efficient of linear expansion ()of the metal of the pendulum shaft are respectively.

  1. ${60^ \circ }C;\alpha = 1.85 \times {10^{ - 4}}/{}^oC$
  2. ${30^ \circ }C;\alpha = 1.85 \times {10^{ - 3}}/{}^oC$
  3. ${55^ \circ }C;\alpha = 1.85 \times {10^{ - 2}}/{}^oC$
  4. ${25^ \circ }C;\alpha = 1.85 \times {10^{ - 5}}/{}^oC$
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B Correct answer