Multiple choice

From the top of a light house of height $200$ metres, the angles of depression of two ships on either side of it are observed to be $30^{0}$ and $45^{0}$, then the distance between the ships in metres is

  1. $100 (\sqrt{2}+1)$
  2. $100(\sqrt{2}-1)$
  3. $100(\sqrt{3}+1)$
  4. $200(\sqrt{3}+1)$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Height = 200. Distance 1 = 200 / tan(30) = 200 * sqrt(3). Distance 2 = 200 / tan(45) = 200. Total distance = 200(sqrt(3) + 1).

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