Multiple choice

Find the time period of the meeting of minute hand and second hand of a clock.

  1. $\Rightarrow t = \dfrac{20}{59} min$
  2. $\Rightarrow t = \dfrac{60}{59} min$
  3. $\Rightarrow t = \dfrac{60}{60} min$
  4. $\Rightarrow t = \dfrac{60}{61} min$
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B Correct answer
Explanation

The minute hand moves at 1/60 rev/min. The second hand moves at 1 rev/min. Relative speed = 1 - 1/60 = 59/60 rev/min. Time for one full relative revolution = 1 / (59/60) = 60/59 min.

AI explanation

To find when the minute and second hands meet, calculate their relative speed, which is 60 - 1 = 59 minutes spaces per hour. The time taken to meet is equivalent to completing one full minute space gap, so the time period is the reciprocal of the relative speed. This gives a meeting time of 60/59 minutes.

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