Multiple choice

If the angle of elevation of a tower from a distance of $100$ metres from its foot is $60^{o}$, then the height of the tower is

  1. $100\sqrt{3}m$
  2. $\dfrac{100}{\sqrt{3}}m$
  3. $50\sqrt{3}m$
  4. $\dfrac{200}{\sqrt{3}}m$
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A Correct answer
Explanation

Height = Distance * tan(60). Height = 100 * sqrt(3).

AI explanation

Using the basic trigonometric ratio for a right-angled triangle, tan(60) equals the height of the tower divided by its distance from the foot. Since tan(60) is sqrt(3), we have sqrt(3) = height / 100. Multiplying both sides by 100 gives the height of the tower as 100 sqrt(3) m.