If $\displaystyle \sum_{i = 1}^{9}(x_{i} - 5) = 9$ and $\displaystyle \sum_{i = 1}^{9}(x_{i} - 5)^{2} = 45$, then the standard deviation of the $9$ items $x_{1}, x_{2}, ...., x_{9}$ is
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If $\displaystyle \sum_{i = 1}^{9}(x_{i} - 5) = 9$ and $\displaystyle \sum_{i = 1}^{9}(x_{i} - 5)^{2} = 45$, then the standard deviation of the $9$ items $x_{1}, x_{2}, ...., x_{9}$ is