Multiple choice

A clock pendulum having coefficient of linear expansion $\alpha =9\times 10^{-7}/^o$C has a period of $0.5$s at $20^o$C. If the clock is used in a climate where the temperature is $30^o$C, how much times does the clock lose in each oscillation? (g$=$constant)

  1. $2.5\times 10^{-7}$s
  2. $5\times 10^{-7}$s
  3. $1.125\times 10^{-6}$s
  4. $2.25\times 10^{-6}$s
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The change in period is given by delta T = (1/2) * alpha * delta theta * T. delta T = 0.5 * 9 * 10^-7 * 10 * 0.5 = 2.25 * 10^-6 seconds.

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