Multiple choice

Find the angle of depression of a boat from the bridge at a horizontal distance of $25$m from the bridge, if the height of the bridge is $25$ m.

  1. $60^0$
  2. $30^0$ 
  3. $45^0$ 

  4. none
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C Correct answer
Explanation

Angle of depression = tan^-1(height / distance) = tan^-1(25 / 25) = tan^-1(1) = 45 degrees.

AI explanation

Using the tangent ratio for the right triangle formed by the bridge and the boat, we get tan(angle of depression) equals the opposite side divided by the adjacent side. Substituting the given values gives tan(theta) equals 25 divided by 25, which is 1. Therefore, the angle of depression is 45 degrees.

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