Multiple choice

The angle of depression of a ship from the top of a tower 30 m height has measure 60. Then, the distance of the ship from the base of the tower is ........

  1. $10$
  2. $30$
  3. $10\sqrt { 3 } $
  4. $30\sqrt { 3 } $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The angle of depression is 60 degrees, so the angle of elevation from the ship is 60 degrees. tan(60) = height / distance. sqrt(3) = 30 / distance. distance = 30 / sqrt(3) = 10 * sqrt(3).