Multiple choice

Divide $32$ into two parts such that if the larger is divided by the smaller, the quotient is $2$ and the remainder is $5$.

  1. The smaller number is $6$ and larger number is $30$.
  2. The smaller number is $9$ and larger number is $23$.
  3. The smaller number is $8$ and larger number is $14$.
  4. The smaller number is $3$ and larger number is $19$.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let x be the smaller and y be the larger. x + y = 32. y = 2x + 5. Substitute: x + (2x + 5) = 32 -> 3x = 27 -> x = 9. Then y = 32 - 9 = 23.

AI explanation

Let the smaller part be x, making the larger part 32 minus x. Applying the division algorithm, the larger part equals the divisor multiplied by the quotient plus the remainder, giving the equation 32 minus x equals 2x plus 5. Solving this, 3x equals 27, so x equals 9. Therefore, the smaller number is 9 and the larger number is 23.

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