In right angled $ \triangle ABC, \angle B = 90^{\circ}$ and $\angle A = \theta$, then $\cos (90 - \theta) = $
Reveal answer
Fill a bubble to check yourself
In right angled $ \triangle ABC, \angle B = 90^{\circ}$ and $\angle A = \theta$, then $\cos (90 - \theta) = $