In right angle $\triangle ABD, \angle B={ 60 }^{ o }, \angle A={ 30 }^{ o }$, then $\cot { { 60 }^{ o } } =$
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In right angle $\triangle ABD, \angle B={ 60 }^{ o }, \angle A={ 30 }^{ o }$, then $\cot { { 60 }^{ o } } =$