Multiple choice

The smallest three digit number when divided by 12, 16 and 18 leaves in each case a remainder 5, is

  1. 149

  2. 293

  3. 337

  4. 481
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A Correct answer
Explanation

Find the LCM of 12, 16, and 18, which is 144. To leave a remainder of 5, the number must be 144 + 5 = 149.

AI explanation

We first find the least common multiple of the divisors 12, 16 and 18, which gives 144. Since the required number must leave a remainder of 5 in each case, we use the formula by adding the remainder to the least common multiple. Adding 5 to 144 gives 149, which is the smallest three-digit number satisfying the condition.

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