Multiple choice

The average of 10 numbers is 53 if the average of the first 4 numbers is 63 and the average of the last 4 numbers is 47, then the average of the remaining two numbers will be ?

  1. 45

  2. 90

  3. 47

  4. 53

  5. None of these
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A Correct answer
Explanation

Total of 10 numbers = 10 × 53 = 530. Sum of first 4 = 4 × 63 = 252. Sum of last 4 = 4 × 47 = 188. Sum of remaining 2 numbers = 530 - 252 - 188 = 90. Average of remaining 2 = 90/2 = 45. This uses the weighted average principle.

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