Find the correct relationship between the given quantities: Quantity I: The present average weight of 15 students of a class, if earlier, the average weight of 14 students, each weighing 1.5 kg more then the present weight, was 56kg and now a new boy weighing 50 kg was added as the 15th student. Quantity II: The number of ways 3 people from 3 men and 3 women can be selected and arranged on 3 chairs such that atmost one of them is a woman.

Quantity I: If 14 students had average weight of 56 kg when each weighed 1.5 kg more, then their present average weight = 56 - 1.5 = 54.5 kg. Adding a 15th student weighing 50 kg, new average = (14×54.5 + 50)/15 = (763 + 50)/15 = 813/15 = 54.2 kg. Quantity II: Selecting and arranging 3 people from 3 men and 3 women with at most one woman. Cases: 0 women (3 men): 3P₃ = 6 ways. 1 woman (2 men): C(3,1) × C(3,2) × 3! = 3 × 3 × 6 = 54 ways. Total = 60 ways. Since 60 > 54.2, Quantity II > Quantity I.