Multiple choice

In each of these questions, two equations (a) and (b) are given. You have to solve both the equations and choose the correct option. a) (2x^2 – x - 78 = 0) b) (y^2 + 26y + 168 = 0)

  1. x > y

  2. x ≤ y

  3. x ≥ y

  4. x < y

  5. x = y or relationship between x and y can't be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation (a): 2x^2-x-78=0 gives x=(1±√(1+624))/4=(1±25)/4, so x=6.5 or x=-6. Solving equation (b): y^2+26y+168=0 gives y=(-26±√(676-672))/2=(-26±2)/2, so y=-12 or y=-14. Since x values (6.5, -6) are always greater than y values (-12, -14), x > y is always true. Option A is correct.

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