Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer. इनमें से प्रत्येक प्रश्न में दो समीकरण (I) और (II) दिए गए हैं। आपको दोनों समीकरणों को हल करना है और उत्तर देना है। I. 2x2 + 3x – 35 = 0 II. 4y2 + 10y – 104 = 0

  1. x > y

  2. x ≤ y

  3. x ≥ y

  4. x < y

  5. x = y or relationship between x and y can't be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve equation I: 2x² + 3x - 35 = 0 factors to (2x - 7)(x + 5) = 0, so x = 3.5 or x = -5. Solve equation II: 4y² + 10y - 104 = 0. Divide by 2: 2y² + 5y - 52 = 0. Using quadratic formula: y = (-5 ± √(25 + 416))/4 = (-5 ± √441)/4 = (-5 ± 21)/4, so y = 4 or y = -6.5. When x = -5, both x < y (y=4) and x > y (y=-6.5) are possible. The relationship cannot be uniquely established.

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