Multiple choice

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer. $I. (x^2 - 10x + 16 = 0) II. (y^2 - 7y + 10 = 0)$

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$

  5. x = y or relation between x and y can not be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: x² - 10x + 16 = (x-2)(x-8) = 0, so x = 2 or 8. Equation II: y² - 7y + 10 = (y-2)(y-5) = 0, so y = 2 or 5. Comparing: x can be > y (8 > 5, 8 > 2), x = y (2 = 2), or x < y (2 < 5). No consistent relation.

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