Multiple choice

$(12x^2 + x - 13 = 0 )(6y^2 + 11y + 3 = 0)$ Find the value of variables and state the correct relationship

  1. $\(x < y\)$
  2. $\(x > y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. x = y or Relation cannot be established
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E Correct answer
Explanation

Solving 12x² + x - 13 = 0 gives x = 1 or x = -13/12. Solving 6y² + 11y + 3 = 0 gives y = -3/2 or y = -1/3. Since x has two possible values and y has two possible values, the relationship depends on which root you take. For x=1, x > both y values. For x=-13/12, x can be greater than y=-3/2 but less than y=-1/3. Thus no single relationship holds in all cases.

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