Multiple choice

Find the value of variables and state the correct relationship-(2x^2+19x+35=0 )(y^2+3y+2=0)

  1. x < y

  2. x > y

  3. x ≤ y

  4. x ≥ y

  5. x = y or Relation cannot be established
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A Correct answer
Explanation

Solving 2x²+19x+35=0: Using quadratic formula or factorization, roots are x = -1.43 and x = -12.5. Solving y²+3y+2=0: Factorizing as (y+2)(y+1)=0, roots are y = -2 and y = -1. All x values (-1.43, -12.5) are less than all y values (-2, -1), therefore x < y. The relationship is consistently x < y across all root combinations.

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