Multiple choice

In each of the following questions, two equations I and II are given. You have to solve them and Give answer निम्नलिखित प्रश्नों में दो समीकरण I और II दिए गए हैं। इन दोनों को हल करके निम्नानुसार उत्तर दीजिए- 1. x3 – 15x = (20 – x) × 15 + 212 2. 2y2 – 13y + 15 = 0

  1. If x > y यदि x > y

  2. If x ≤ y यदि x ≤ y

  3. If x < y यदि x < y

  4. If x ≥ y यदि x ≥ y

  5. If x = y or relationship cannot be established यदि x = y या सम्बन्ध ज्ञात नहीं किया जा सकता
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Equation I: x³ - 15x = (20 - x) × 15 + 212 simplifies to x³ - 15x = 300 - 15x + 212, giving x³ = 512, so x = 8. Equation II: 2y² - 13y + 15 = 0 gives (2y - 3)(y - 5) = 0, so y = 1.5 or y = 5. Since x = 8 > 1.5, 5, option A (x > y) is correct.

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