Multiple choice

$(x^2 = 256)$ $(y^2 + 18y + 17 = 0)$ On the basis of these equations, decide the relation between ‘x’ and ‘y’.

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$

  5. x = y or no relation can be established between x and y
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For x² = 256, x = ±16. For y² + 18y + 17 = 0, factoring gives (y+1)(y+17) = 0, so y = -1 or y = -17. When x = 16, x > y (both y values are negative). When x = -16, x > -17 but x < -1. Since x can be greater or less than y depending on the values, no single relation can be established. Option E is correct.

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