Multiple choice

The average price of 10 chocolates is Rs. 12 while the average price of 8 of the chocolates is 11.75. If the price of one of the remaining chocolates is 60% more than the second remaining chocolates. Find the price of cheaper chocolates.

  1. 16

  2. 15

  3. 12

  4. 10

  5. 8
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total sum = 10 × 12 = Rs. 120. Sum of 8 chocolates = 8 × 11.75 = Rs. 94. Sum of remaining 2 chocolates = 120 - 94 = Rs. 26. Let cheaper chocolate cost x, expensive = 1.6x (60% more). So x + 1.6x = 2.6x = 26, x = 10. Cheaper chocolate costs Rs. 10.

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