Multiple choice

In the following question two equations I and II are given. You have to solve both the equations and give answer. निम्नलिखित प्रश्न में दो समीकरणों I और II दिए गए हैं।इन दोनों समीकरणों को हल करके निम्नानुसार उत्तर दीजिए। (I) (x + 3)2 - 25 = 0 (II) y2 - 14y + 49 = 0

  1. If x < y यदि x < y

  2. If x > y यदि x > y

  3. If x ≤ y यदि x ≤ y

  4. If x ≥ y यदि x ≥ y

  5. If x = y or the relationship cannot be determined यदि x = y या संबंध स्थापित नहीं किया जा सकता
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A Correct answer
Explanation

Solving (x + 3)² - 25 = 0 gives (x + 3)² = 25, so x + 3 = 5 or x + 3 = -5. Therefore x = 2 or x = -8. Solving y² - 14y + 49 = 0 gives (y - 7)² = 0, so y = 7 (repeated root). Comparing the values: both x = 2 and x = -8 are less than y = 7. Therefore x < y is always true.

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