Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and state the correct relationship. $I. (5x^2 + 28x = -15)$ $II. (3y^2 + 11y + 6 = 0)$

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. X = Y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve equation I: 5x² + 28x + 15 = 0 gives x = -0.6, -5. Solve equation II: 3y² + 11y + 6 = 0 gives y = -2/3, -3. Since x has values both less than and greater than y (e.g., -5 < -3 and -0.6 > -2/3), no consistent inequality relationship exists.

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