Multiple choice

(\text{In each of the following questions, two equations are given. You have to solve them})(\text{(I)}) (3x^2 - 4x - 4 = 0 )(\text{(II)}) (3y^2 + 14y + 8 = 0)

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$
  5. $\(x = y \text{ or relation can't be established}\)$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve (I): 3x² - 4x - 4 = 0 gives x = 2 or x = -2/3. Solve (II): 3y² + 14y + 8 = 0 gives y = -2/3 or y = -4. Comparing: 2 ≥ -2/3, 2 ≥ -4, -2/3 ≥ -2/3, -2/3 ≥ -4. So x ≥ y in all cases.

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