Multiple choice

In each of the following questions, two equations are given, you have to solve them and-\newline I. (y^2 - 0.7y + 0.12 = 0)\newline II. (x^2 + 0.1 \times x - 0.12 = 0)

  1. x < y

  2. x > y

  3. x ≥ y

  4. x ≤ y

  5. x = y or relationship cannot be established.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solve each quadratic equation. For I (y²-0.7y+0.12=0): factors as (y-0.4)(y-0.3)=0, so y=0.4 or 0.3. For II (x²+0.1x-0.12=0): factors as (x+0.4)(x-0.3)=0, so x=0.4 or -0.3. Comparing all four combinations, x is always less than or equal to y.

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