Multiple choice

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. $I. (9x^2 - 45x + 56 = 0) (II. 4y^2 - 17y + 18 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or relationship between x and y cannot be determined
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Equation I: 9x² - 45x + 56 = 0. Using quadratic formula: x = (45 ± √(2025-2016))/18 = (45 ± 3)/18, so x = 48/18 = 8/3 ≈ 2.67 or x = 42/18 = 7/2 = 3.5. Equation II: 4y² - 17y + 18 = 0. Using quadratic formula: y = (17 ± √(289-288))/8 = (17 ± 1)/8, so y = 18/8 = 9/4 = 2.25 or y = 16/8 = 2. Comparing: 8/3 > 9/4 (2.67 > 2.25), 8/3 > 2, 7/2 > 9/4 (3.5 > 2.25), 7/2 > 2. In all cases, x > y. Option A is correct.

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