Multiple choice

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. $I. (4x^2 + 16x + 15 = 0) \nII. (2y^2 + 3y + 1 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or relationship between x and y cannot be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Equation I: 4x² + 16x + 15 = 0 factors as (2x+3)(2x+5)=0, so x = -3/2 or x = -5/2. These are x = -1.5 and x = -2.5. Equation II: 2y² + 3y + 1 = 0 factors as (2y+1)(y+1)=0, so y = -1/2 or y = -1. These are y = -0.5 and y = -1. Comparing: -1.5 < -0.5 (x

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